Particle A moves with a constant speed 2m/s on a circular path of radius 4m, whereas particle B moves on a straight-line coinciding with a diameter of the circular path, maintaining a constant distance 4m from the particle A. Which of the following conclusions can be drawn?a)Maximum speed of B is 4m/s
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Answer:
Radial acceleration a
r
=ω
2
r=
r
v
2
=2
2
/4=1cm
2
/s
Now this acceleration is directed toward origin in third quadrant.
Component of acceleration along negative x axis is a
x
=−a
r
cos45
x
^
Component of acceleration along negative y axis is a
y
=−a
r
sin45
y
^
a
r
=a
x
+a
y
=
2
−(
x
^
+
y
^
)
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