Question

Particle A moves with a constant speed 2m/s on a circular path of radius 4m, whereas particle B moves on a straight-line coinciding with a diameter of the circular path, maintaining a constant distance 4m from the particle A. Which of the following conclusions can be drawn?Maximum speed of B is 4m/sModulus of velocity of a particle relative to the other is a constantc).During one revolution of A, distance travelled by B is 32m​

Answer 1

Answer:

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Explanation:

Radial acceleration a

r

=ω

2

r=

r

v

2

=2

2

/4=1cm

2

/s

Now this acceleration is directed toward origin in third quadrant.

Component of acceleration along negative x axis is a

x

=−a

r

cos45

x

^

Component of acceleration along negative y axis is a

y

=−a

r

sin45

y

^

a

r

=a

x

+a

y

=

2

−(

x

^

+

y

^

)