Question

particle initially at rest moves with an acceleration 5 metre per second square for 5 seconds find the distance travelled in 4 second​

Answer 1

h= ut+1/2at^2

h1 = 0 + 1/2 (5) (4) ^2

h1=5*8

h1=40m

h2= 0 + 1/2 (5)(5)^2

h2= 25m Please mark as branliest

Answer 2

Answer:

Hey mate!!! here is your answer

Explanation:

an acceleration 5m/s square for 5 sec . Find distance travelled in 4 s ,5s and 5 th second - 4377162.Is your answer.. broh!!!!

We know

H=ut+1by2 at square

For the first Equat... H1=5×8= 40

Hence H1=40m

On same for 2nd equat...

H2=0+1by2 (5)(5)^2

And h2= 25m

Hope my answer helps you....

Mark me as Brainliest.....