particle initially at rest moves with an uniform acceleration of 10m/s and attains a velocity of 90m/s after some time .the time taken to travel a distance of 45 m is
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Explanation:
uniform velocity, u= 0m/s
final velocity, v= 90m/s
acceleration, a= 10m/s²
distance, s=45m
time,t= ?
s= ut+½at²
45= (0×t)+(½× 10×t)
45 = ½×10t²
45×2= t²
90/10 =t²
root 9 = t
3 = t
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