Question

Particle is moving along a circular path of radius 6 m with uniform speed of 8 metre per second the average acceleration when the particle completes one half of the revolution is

Answer 1

avg accn is change in velocity vector in atime interval

Answer 2

ANSWER:

Average acceleration $A = 5.33 m / \mathrm{sec}^{2}$

EXPLANATION:

Average acceleration of the moving particle in a circle is = average velocity/time

Average velocity of the moving particle is anticipated as = displacement/time

Therefore, the Average velocity of the particle is taken as

$V_{A V}=\frac{2 r}{t}$

$8=\frac{2 \times 6}{t}$

$t=1.5 \mathrm{sec}$

Now calculating the average acceleration of the particle is $A_{a v}=\frac{v}{t}=\frac{8}{1.5}=5.33 \mathrm{m} /\mathrm{sec}^{2}$

Therefore, the average acceleration of the average velocity of the particle calculated is 5 m/sec within 4 sec is given as per calculation as average acceleration $A = 5.33 m / \mathrm{sec}^{2}$