Question

particle is moving in a circle of radius 4 cmn with constant speed of 1 cm/s. Find a) time period of the particle
b) average speed, average velocity and average acceleration in a time interval from t =0 to
t =T/4. Here, Tis the time period of the particle. Give only their magnitudes.​

Answer 1

Answer:

Answer :

A::B::C

Solution :

(a) T=2πRv=25.13s

(b) (i) Since speed is constant.Therefore,

average speed=constant speed

=1.0cm/s

(ii) Average velocity=st=2–√RT/4=42–√RT

=(4)(2–√)(4.0)25.13=0.9cm/s

(iii) Velocity vector will rotate 90∘

∴|(Δv)|=(v2+v2−2vvcos90∘−−−−−−−−−−−−−−−−√)

=2–√v

∴|aav|=∣∣∣ΔvΔt∣∣∣=2–√vT/4=42–√vT

=(42–√)(1.0)25.13=0.23cm/s2

Explanation: