particle is moving in a circular path of radius r find magnitude of displacement of particle after covering 3/4th of circle
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displacement : displacement is the minimum path covered by particle or it is the difference of final position to initial position.
Let particle starts to move from A, after completing 3/4th part of circle particle stops at point B.
so, displacement of particle = length of AB [ as shown in figure ]
if we assume O is the centre of circle,
then, ∆AOB is isosceles right angled triangle.
length of AB = hypotenuse
radius of circle = base = height
from Pythagoras theorem,
so, length of AB² = r² + r² = 2r²
or, length of AB = √2r
hence, displacement of particle is √2r
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