Question

particle is projected from ground with an initial velocity of 20 metre per second at an angle 30 degree with horizontal the magnitude of change in velocity and time interval 0.5 second starting from instant of projection is​

Answer 1

Answer:

Given, u = 20 m/s

         θ = 300

Assuming that your question was about change in magnitutde of Velocity, we can say

 

ux = u cosθ = 20xcos30 = 20x = 10m/s

uy = u sinθ = 20xsin30 = 20x1/2 = 10 m/s

 

ax = 0 m/s2

ay = -g = -10 m/s2

 

Now change in velocity after 0.5 seconds is,

 

vx = ux + axt = 10 + 0 = 10 m/s

vy = uy + ayt = 10 + (-10x0.5) = 10-5 = 5 m/s

 

So, the magnitude of final velocity after 0.5 seconds is, v =  

therefore, v =  

                =  

                =  

                = 18.03 m/s

Explanation: