Question

particle is projected to certain velocity at an angle in about the horizontal from the foot of an inclined plane of inclination 30° . if the particle strikes the plane normally then a is equals to option A 30 degree + tan inverse root 3 by 2 option B 45 degree option C 60 degree option d 30 degree + tan inverse root 2 root 3

Answer 1

time of flight of the projectile
= 2u sin(α − 30°)
Now component of velocity along the plane becomes zero at point B.
0 = u cos(α − 30°) − g sin 30°T
= u cos(α − 30°) = (gsin30°) 2u sin(α − 30°)
= tan(α − 30° ) = tan 30° 2 1 2√ 3
α = 30° + (tan ^ −1 )(root 3/2 )

Answer 2

Answer:

hey mate here is your answer