Question

Particle is projected vertically upward from a point a on the ground it takes t1 time to reach point b but it still continues to move up if it takes for that you to time to reach the ground from point b then height of point b from the ground is

Answer 1

Answer:

1/2g t1 t2

Explanation:

total time of particle = t1 + t2

to find initial value

Applying 2nd equation of motion

o = u(t1 + t2) -g/2 (t1 + t2)²

=> g/2 ( t1 + t2 ) = u [ height at t = t1 + t2 is zero]

At t = t1 , height attained is l

So,

h = u t1 – g/2 t1²

h = g/2 (t1 + t2) t1 – g/2 t1²

h = g/2 ( t1 + t2 – t1 )

h = g/2 t1 t2

The height of point B(h) is gt1t2 / 2 ...