Physics, asked by keshavdashrathamz, 26 days ago

particle is projected vertically upwards with a of speed 105 m/s. The distance travelled by the particle in the 11th second of its motion is: (g = 10m/s^2​

Answers

Answered by rajdeepbiswas3305
0

Answer:

260m

Explanation:

please mark me brainliest

Similar questions