Question

Particle is projected with velocity of 3i+4j m/s. find angle of projection

Answer 1

Given : Particle is projected with velocity of 3i+4j m/s.

To find  : angle of projection

Solution:

Particle is projected with velocity of 3i+4j m/s.

Angle of projection = α

Tanα =  4/3

=> α = Tan⁻¹( 4/3)

=> α =  53°

angle of projection =  53°

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Answer 2

Given:

Particle is projected with velocity of 3i+4j m/s.

To find:

Angle of projection?

Calculation:

• Let angle of projection be $\theta$.

So, let's take the ratio of components of initial velocity.

$\rm \therefore \: \dfrac{ u_{y} }{ u_{x} } = \dfrac{4}{3}$

$\rm \implies\: \dfrac{ u \sin( \theta) }{ u \cos( \theta) } = \dfrac{4}{3}$

$\rm \implies\: \dfrac{ \sin( \theta) }{ \cos( \theta) } = \dfrac{4}{3}$

$\rm \implies\: \tan( \theta) = \dfrac{4}{3}$

$\rm \implies\: \theta = { \tan}^{ - 1} ( \dfrac{4}{3} )$

$\rm \implies\: \theta = {53}^{ \circ}$

So, angle of projection is 53° to the horizontal.