Physics, asked by mahipalsaini200, 6 months ago

Particle moves a certain distance in a straight line as follows. First one third distance at V1 and next two third distance at V2 then its average speed will be

Answers

Answered by smitaprangya98
3

Explanation:

Average speed = total distance covered /total time taken

let the total distance =3x

time taken to cover first one third (x) = t1 = x/v1

time taken to cover second one third =t2= x/v2

time taken to cover 3rd one third = t3= x/v3

average speed = 3x/(x/v1 +x/v2+x/v3)

Answered by Anonymous
1

Answer:

Average speed = total distance covered /total time taken

let the total distance =3x

time taken to cover first one third (x) = t1 = x/v1

time taken to cover second one third =t2= x/v2

time taken to cover 3rd one third = t3= x/v3

average speed = 3x/(x/v1 +x/v2+x/v3)

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