Question

Particle moves along a circle of radius 20 by pi with constant tangential acceleration velocity of particle is it at the end of second revolution after motion has been and tangential acceleration is

Answer 1

Complete Question: Particle moves along a circle of radius 20 by pi with constant tangential acceleration. If the velocity of particle is 80 m/s at the end of second revolution after motion has begun, then the tangential acceleration is?

Answer:

Tangential Acceleration, At = 40 m/s²

Explanation:

[The condition given refers to Non Uniform Accelerated Motion]

Given:-

              Radius, R= 20/π m

At End of 2nd Revolution, Vf = 80 m/s [where Vf is Final Velocity]

Then:-

Let us assume that the initial velocity was Ui = 0.

Let the tangential acceleration be At.

Also, path length after 2 revolutions= 2π × 2= 4π R = S

From 3rd equation of motion we have;-

              v² - u² = 2as

So, in this case, putting all the given values, we get;-

           80² - 0² = 2 × At × 4π R

           80 × 80 = 2 × At × 4π × 20/π   [since, R= 20/π]

           80 × 40 = At × 80

                    At = 40 m/s²

Hence, the value of tangential acceleration is 40 m/s².

Hope it helps! ;-))