Physics, asked by snigdhays2020, 19 days ago

particle moves along a circle with constant speed2 ms−1 . If it completes1/4th of rotation, change in its velocity ​

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Answered by rite2dev
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Answer:

The change in velocity of a particle moving along a circle with constant speed of 2 m/s, after completing 1/4th of rotation, can be calculated using the formula for centripetal acceleration (a = v^2/r), where v is the velocity of the particle and r is the radius of the circle. The centripetal acceleration is directed towards the center of the circle and changes the direction of velocity. In this case, the change in velocity would be equal to the centripetal acceleration multiplied by the time taken for 1/4th of rotation. The exact value can be calculated with the given information.

Explanation:

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