Question

particle moves along a circle with constant speed2 ms−1 . If it completes1/4th of rotation, change in its velocity​

Answer 1

Explanation:

after completing 1/4th of the circle the angle between initial and final velocities is 90

∘

so ∣

v

2

−

v

1

∣=

v

1

2

+v

2

2

−2v

1

v

2

cosθ

=

2

2

+2

2

m/s

= 2

2

m/s which is the change in the velocity.

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