Question

particle moves along a straight line such that
3 its displacementat any time t is given by
s = (t 3 – 6+2+ 3+ + 4) metre
The velocity when acceleration is zero
-​

Answer 1

Answer:

S=t

3

−6

2

+3t+4

v=

dt

ds

So =3t

2

−12+3=v

again differentiate ,a=

dt

dv

6t−12=0

t=2s

v=3(2)

2

−12×2+3=−9ms

−1

Explanation:

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