Question

particle moves along the X - axis starting from x=+2m at t=0. At t=5s it is at x=+8m and at t=12s it is at x=-12m. The displacementof the particle in 12s​

Answer 1

Explanation:

hlo mate here's your answer

Correct option is

A the initial velocity of the particle is

u

C the acceleration of the particle is

2α

D at

t=

2s

particle is at the origin.

We know,

v=

d t

d x

= u+ 2a(t− 2) (1)

a=

d t 2

d 2 x

=

2a (2)

Here we will discuss all the option,

Case 1

Initial velocity means, v at t=0,

i.e ,

v=

u−

4a=

u

Option A is correct.

Case 2

It is clear from equation (1) that ,

Acceleration

=

2a

Option B is incorrect and option C is correct.

At t=2s,

x= 0 i.e particle is ar origin.

Option D is correct.

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Answer 2

Explanation:

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