Question

Particle of mass m and charge q is in an electric and magnetic field given by e 2i 3j ; b 4j 6k . The charged particle is shifted from the origin to the point p(x = 1 ; y = 1) along a straight path. The magnitude of the total work done is :-

Answer 1

The magnitude of the total work done is ω = 5q

Explanation:

Given data:

• Electric field = 2i 3j
• Magnetic field = 4j 6k
• Shifting point =  p(x = 1 ; y = 1)

Solution:

F = qE + q ( V x B)

Now put the values in this equation:

F = (2qi + 3qj) + q [V x B ]

ω= F(net) . S = 2q  + 3q

ω = 5q

Hence the magnitude of the total work done is ω = 5q

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