particle travels 1st half of the total distance with speed v1 in 2nd half distance constant speed in1/3 time in v2 and remaining 2/3 time constant speed is v3 find average speed during the complete journey
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Answer:
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Explanation:
Average speed (v
avg
)=
Time
(Total)
Distance
(Total)
=
Σt
i
Σv
i
t
i
So, Average speed =
t
v
1
(
2
t
)+v
2
(
2
t
)(
3
1
)+v
3
(
2
t
)(
3
2
)
⇒v
avg
=
2
v
1
+
6
v
2
3
v
3
=
6
(3v
1
+v
2
+2v
3
)
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