Particles moves along the x-axis according to the equation x= 3t^2 - 2t + 3, where x is in meters and t is in seconds at t= 3s. Find a.) the position of the particle b.) it's velocity c.) it's acceleration
Answers
Answered by
0
Explanation:
The position of a particle moving along x-axis is given by
x=(−2t
3
+3t
2
+5)m
Velocity, v=
dt
dx
=0
−6t
2
+6t=0. . . . . . .(1)
6t(−t+1)=0
−t+1=0
t=1sec
Acceleration, a=
dt
dv
a=−12t+6
a∣
t=1sec
=−12×1+6
a∣
t=1sec
=−6m/s
2
The correct option is C.
Answered by
0
Answer:
here is ur answer
Explanation:
The position of a particle moving along x-axis is given by
x=(−2t3+3t2+5)m
Velocity, v=dtdx=0
−6t2+6t=0. . . . . . .(1)
6t(−t+1)=0
−t+1=0
t=1sec
Acceleration, a=dtdv
a=−12t+6
a∣t=1sec=−12×1+6
a∣t=1sec=−6m/s2
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