Question

particles
The weight of iron which will be converted into its oxide (Fe:0.) by the action of 18 g of
steam on it will be (atomic weight of Fe = 56)
a) 168 g
b) 843
c) 422
d) 21 g​

Answer 1

The reaction occurs as 3Fe+4H2O→Fe3O4+4H23Fe+4H2O→Fe3O4+4H2

Mole ratio of reaction suggest

MoleofFeMoleofH2O=34MoleofFeMoleofH2O=34

Mole of Fe=1818×34Fe=1818×34

Weight of Fe=3434×56=42g×56=42g

Hence (c) is the correct option.