Question

particular integral of (D2 + 4D + 4y = sint is
Select one:
[4sinx - 3cosx
–
)
O a.
1
25
O b. [3sinx – 4cost)
O c. [3sinx
[3sinr – 4cosx
h
O d. [4sinx - 3cosx ]​

Answer 1

Answer:

5x

3 -3−

3x

2)2)

÷x2Which of the following statements is not true for the chemical equation?

2N₂O, → 4NO₂ + O₂

(A) 2 mol of N₂O, on dissociation gives 4 mol of NO, and 1 mol of O

(B) 1 mol of N₂O5 on dissociation gives 2 mol of NO, and 0.5 mol of O (C) 2 g of N₂O, on dissociation gives 4 g of NO and 1 g of O₂

(D) 216 g of N₂O, on dissociation gives 184 g of NO, and 32 g of O₂5x

$3 -$

3x

$2)$

÷x2

Step-by-step explanation:

5x

3 -3−

3x

2)2)

÷x2Which of the following statements is not true for the chemical equation?

2N₂O, → 4NO₂ + O₂

(A) 2 mol of N₂O, on dissociation gives 4 mol of NO, and 1 mol of O

(B) 1 mol of N₂O5 on dissociation gives 2 mol of NO, and 0.5 mol of O (C) 2 g of N₂O, on dissociation gives 4 g of NO and 1 g of O₂

(D) 216 g of N₂O, on dissociation gives 184 g of NO, and 32 g of O₂5x

$3 -$

3x

$2)$

÷x2

5x

3 -3−

3x

2)2)

÷x2Which of the following statements is not true for the chemical equation?

2N₂O, → 4NO₂ + O₂

(A) 2 mol of N₂O, on dissociation gives 4 mol of NO, and 1 mol of O

(B) 1 mol of N₂O5 on dissociation gives 2 mol of NO, and 0.5 mol of O (C) 2 g of N₂O, on dissociation gives 4 g of NO and 1 g of O₂

(D) 216 g of N₂O, on dissociation gives 184 g of NO, and 32 g of O₂5x

$3 -$

3x

$2)$

÷x2