parts of ₹81 when it is divided amongst A,B,C so that B may be ₹7 more than AandC ₹6 less than twice A share, are
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Total amount 81 =a+b+c
Let A be x
B= ₹x + 7
C=. ₹2x - 6
According to the question
x + (x +7) + (2x - 6) =81
x+x+7 +2x - 6=81
4x + 1 =81. ( transposing)
4x=81 - 1
4x=80
x = 80/4
x= 20
Share of a is 20
Share of B is (x + 7)=27
Share of c (2x-6)=2 * 20 - 6 =34
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