Question

partunits. As [ UTD 3x 2-1247-|| 2 27-3441020 12 -3x-12y=-11
2x-3y+10=0
draw the graph ..​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

if a person travels at the speed of 30 km/h, then he reaches his destination 10 minutes late, while traveling at the speed of 42 km/h, he reaches his destination 10 minutes before.

To find:-

The distance traveled by a person..

Solution:-

Let the actual time taken to reach the destination by man be x

Case 1: If speed of man, u=30 km/h

He reaches his destination 10 minute late..

\sf \pink{Example:}Example: Distance between man & destination point, S=speed of man × Time taken..

Main Point:-

10 min=\dfrac{10}{60}

60

10

=\dfrac{1}{6}

6

1

So,

S=30×(Time+\dfrac{1}{6})

6

1

) . [\sf \pink{Step 1:}]Step1:]

Case 2: If speed of man v=42km/h, he reaches his destination 10 minutes early..

\sf \pink{Example:}Example: Distance between man & destination point, S=speed of man × Time taken..

=42×(Time-\dfrac{1}{6})

6

1

) km [\sf \pink{Step 2:}]Step2:]

Now, from equations (1) & (2),

30(Time+\dfrac{1}{6})

6

1

) =42(Time-\dfrac{1}{6})

6

1

)

Therefore 10 T+\dfrac{10}{6}

6

10

=14 T-\dfrac{14}{6}

6

14

Therefore \dfrac{10}{6}

6

10

+\dfrac{14}{6}

6

14

=14 T-10 T

Therefore \dfrac{24}{6}

6

24

=4 T

Or Time= 1 hour..

By putting T in \sf \pink{Step 1}Step1

S=30(1+\dfrac{1}{6})

6

1

) =30×\dfrac{7}{6}

6

7

=35 km

________________

Hence, the distance traveled is 35 km..