Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m x 3 m?
Answers
Answer:
tarpaulin would be required to make the shelter = 47 m²
Step-by-step explanation:
Total Area required
= 4 * 2.5 + 4 * 2.5 + 3 * 2.5 + 3 * 2 .5 + 4 * 3
= 10 + 10 + 7.5 + 7.5 + 12
= 47
stitching margins are very small, and therefore negligible
tarpaulin would be required to make the shelter = 47 m²
Answer:
Area of the tarpaulin required, A = 47 square metre
Step-by-step explanation:
In the question,
There are 5 faces in total with the front face capable of rolling up.
Height of the shelter, h = 2.5 m
Length of the shelter, l = 4 m
Width of the shelter, w = 3 m
So,
Area of the cover required, A = 2(h x w) + 2(l x h) + (l x w)
A = 2(2.5 x 3) + 2(4 x 2.5) + (4 x 3)
A = 15 + 20 + 12
A = 47 m square.
Therefore, the area of the tarpaulin required to make the entire cover is equal to 47 metre square.