Question

Parveen wanted to make a temporary shelter for her car by making a box like structure with tarpaulin that covers all the four sides and the top of the car with front face as a flap which can be rolled upon.Assuming that the stitching margins are very small and therefore negligible how much tarpaulin would be required to make the Shelter of height 2.5m with base dimensions 4m*3m.​

Answer 1

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47 sq.m tarpaulin is required to make as shelter

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Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Let l, b and h be the length, breadth and height of the shelter.

Given:

l = 4m

b = 3m

h = 2.5m

Tarpaulin will be required for the top and four wall sides of the shelter.

Using formula, Area of tarpaulin required = 2(lh + bh)+lb

Put the values of l, b and h, we get

= [2(4 × 2.5 + 3 × 2.5) + 4 × 3] m²

= [2(10 + 7.5) + 12]m²

= 47 m²

Therefore, 47 m² tarpaulin will be required