Question

Parveen wanted to make a temporary shelter for her car by making a box like structure with tarpaulin cover all the four side and the top of car assuming that the stitching margin are very small and there for negligible how much Tarpaulin would be required to make the shelter height 2.5m, with base dimension 4m×3m​

Answer 1

Answer:

47m^2

Step-by-step explanation:

Dimensions =4×3m

Height= 2.5m

Area of 4 wall =2h(l+b)

=2×2.5(4+3)

=5×7

=35m^2

Area of roof =(4×3)m^2

=12 m^2

Total area = (12+35)m^2

=47m^2

The base of its is un covered so we don't take it area

Answer 2

Answer:

• Length of shelter = 4m
• Breadth of shelter = 3m
• Height of shelter = 2.5 m

$\large{\underline{\sf{\blue{\therefore\:\:Area\:\:of\:\:trapaulin\:\:required\:\::-}}}}$

$\\ \sf \: 2 \: ( \: lh \: + \: bh) + lb \\ \\ \\ \implies \sf \: 2 \: ( \: 4 \times 2.5 + 3 \times 2.5 \: ) + 4 \times 3 \: \: {m}^{2} \\ \\ \\ \implies \sf \: 2 \: ( \: 10 + 7.5) + 12 \: \: {m}^{2} \\ \\ \\ \implies \sf \red{47 \: \: {m}^{2} }$

Therefore, 47 m² trapaulin will be required.