Question

Parveen wanted to make a temporary shelter, for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m x 3 m?​

Answer 1

Answer:

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Given :-

length (l) = 4 m,

breadth (b) = 3m

and height (h) = 2.5 m

Solution :-

The structure is like a cuboid.

∴ The surface area of the cuboid, excluding the base

=[Lateral surface area] + [Area of ceiling]

= [2(l + b)h] + [lb]

= [2(4 + 3) x 2.5] m² + [4 x 3] m²

= 35 m²+ 12 m² = 47 m²

Thus, 47m² tarpaulin would be required.

Answer 2

Answer:

Dimension of the non-like structure = 4m×3m×2.5m

Tarpaulin only required for all the

for sides and top.

Thus Tarpaulin required = 2(l+b)×h+lb

=[2(4+3)×2.5+4×3]m2

=[35+12]m2

=47m2

Step-by-step explanation:

this is correct answer