Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m x 3 m?
Answers
pls see the given attachment
hope it help uh freind
Answer:
40 cm²
40 cm²Step-by-step explanation:
40 cm²Step-by-step explanation:We know that perimeter of a rectangle (box) is 2(l+b)
40 cm²Step-by-step explanation:We know that perimeter of a rectangle (box) is 2(l+b)Length of the box = 8cm
40 cm²Step-by-step explanation:We know that perimeter of a rectangle (box) is 2(l+b)Length of the box = 8cmBreadth of the box = 12cm
40 cm²
40 cm²Step-by-step explanation:
40 cm²Step-by-step explanation:We know that perimeter of a rectangle (box) is 2(l+b)
40 cm²Step-by-step explanation:We know that perimeter of a rectangle (box) is 2(l+b)Length of the box = 8cm
40 cm²Step-by-step explanation:We know that perimeter of a rectangle (box) is 2(l+b)Length of the box = 8cmBreadth of the box = 12cm