Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible; how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m x 3 m? ✍✍
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Answered by
0
Answer:
47m²
Step-by-step explanation:
length (l) of the shelter = 4m
breadth (b) of the shelter = 3m
height (h) of the shelter = 2.5m
area of tarpaulin = area of cuboid - area of
Answered by
1
Answer:
47m²
Step-by-step explanation:
Length = 4m
Breadth = 3m
Height = 2.5m
Area of tarpaulin used = Area of cuboid - Area of bottom
The shelter covers the 4 sides and the top, the bottom part is left open.
Area of cuboid = 2 (lb + bh + lh)
= 2 ( 4 x 3 + 3 x 2.5 + 4 x 2.5)
= 2 ( 12 + 7.5 + 10)
= 2 x 29.5
= 59m²
Area of bottom = lxb
= 4 x 3
= 12m²
Area of tarpaulin used = 59 - 12 = 47m²
Parveen requires 47m² of tarpaulin to make a temporary shelter for his car
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