Question

PASSAGE-I: An elevator weighing 500 kg is to be lifted up at a constant velocity of 0.4 m s-1. For this purpose a motor of required horse power is used.​?spam=10 answer report​

Answer 1

Step-by-step explanation:

power = work done / time

= mgD

t

= 500x10x0.4 = 2000W

1

=2.68HP[1watt=0.00134HP]