Question

Passage - II : The sum of zeroes = a += -8 and product of zeroes =
aß = 6.

I) A polynomial whose zeroes are ,1/a and 1/ßis


B) 6x2 – 8x - 1
A) 6x2 + 8x + 1
C) 6x2 - 4x + 6
D) 6x² – 8x + 1​

Answer 1

Answer:

A) 6x2+8x+1

Explaination:

k(x2-(@+b)x+@b)

k(x2-(1/@+1/b)x+(1/@)(1/b))

k{x2-(@+b/@b)x+1/@b}

k{x2-(-8/6)x+1/6}

k{x2+8x+6} where k=6

then

6x2+8x+6