Passage of current for 548 seconds through a silver coulometer results in the deposition
of 0.746g of silver. What is the current in Ampere?
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Passage of 1.22 A current for 548 seconds through a silver coulometer results in the deposition
of 0.746g of silver.
- If 1F gives 108g of Ag
Or 96500 Columb gives 108g Ag
1 g of Ag requires
According to question,
0.746g will require
=666.56C
- As Q=It
Therefore required current will be I=Q/t
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