Math, asked by ravikumarroyal123, 1 year ago

passenger, while boarding the plane, slipped from the stairs and got hurt. The pilot tookthe passenger in the emergency clinic at the airport for treatment. Due to this, the plane go delayed by half an hour. To reach the destination 1500 km away in time, so that the passengers could catch the connecting flight, the speed of the plane was increased by 250 km/hour than the usual speed. Find the usual speed of the plane. What value is depicted in this question ?



I am getting the wrong answer..why?...help!

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Answered by aryanbhadoriya411
1

Answer:

Step-by-step explanation:

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A passenger, while boarding the plane, slipped form the stairs and got hurt. The pilot took the passenger in the emergency clinic at the a irport for treatment. Due to this, the plane got delayed by half an hour. To reach the des tination 1500 km

Asked by:tarun101

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Let the usual speed of plane be x km/ hr.

Speed increased by 250 km/hr .

New speed = (x + 250)km/hr

Distance to be covered = 1500 km

Time taken as per usual speed = 1500/x hr

Time taken when speed is increased by 250 km/hr = (1500/x + 250)hr

Acoording to question,

1500/x - 1/2 = 1500/x + 250

1500/x - 1500/x + 250 = 1/2

{1500(x+250) - 1500x}/x(x+250) = 1/2

1500x + 375000 - 1500x = (x²+250x)/2

750000 - x² - 250x = 0

x² + 250x - 750000 = 0

x² + 1000x - 750x - 750000 = 0

x(x+1000) - 750(x+1000) = 0

(x+1000)(x-750) = 0

x = -1000. x = 750

As speed can not be negative, usual speed of the plane is 750 km/ hr .


aryanbhadoriya411: Pls mark as brainliest
Answered by taiogunbekun02
0

Answer:

step-by-step explanation:

initial speed=final speed/time

initial speed=1500 km divided by 250 km

initial speed=6 km

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