Math, asked by artithakre36gmailcom, 10 months ago

passing through (2, 3) and perpendicular to lines 3x+2y-1=0 and x-3 y+2=0​

Answers

Answered by kings07
0
Notes:

Slope of ax + by + c = 0 is – a/b (b ≠ 0) i.e. Slope = – coefficient of x / coefficient of y

When two lines are parallel their slopes are equal.

When two lines are perpendicular to each other then the product of their slopes is -1. Thus, If slope one line is m, then the slope of a line perpendicular to it is – 1/m.

ALGORITHM:

Find the slopes of given line using the formula given in point 1 of notes.

Find the slopes of required lines forming pair using relations given in points 2 and 3 of notes.

Use slope point form  y – y1 =  m (x – x1 ) to find equations of given lines. If Lines are passing through origin use y = mx form.

Write equations of lines in the form u = 0 and  v = 0.

Find u.v = 0.

Simplify the L.H.S. of the joint equation.

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