Passing through (-2,8) and PERPENDICULAR to y=2x+5
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y2-y1/x2-x1=m where m is slope
since this is perpendicular so slope perpendicular to it will be negative reciprocal
Y-8/x+2 =-1/2.............
2y-16=-x-2
x+2y-14=0
since this is perpendicular so slope perpendicular to it will be negative reciprocal
Y-8/x+2 =-1/2.............
2y-16=-x-2
x+2y-14=0
Answered by
1
The line is perpendicular to y = 2x + 5 so its slope is -1/2.
Line passing through (-2,8) having slope -1/2
y-8 = -1/2(x+2)
x + 2y - 14 = 0
Line passing through (-2,8) having slope -1/2
y-8 = -1/2(x+2)
x + 2y - 14 = 0
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