Question

Passing through the foot of the perpendiculars drawn from P (a, b,c) on the co-ordinate planes.​

Answer 1

Answer:

Let the foot of the perpendicular be P(a,b,c).

Then, direction ratios of OP are a−0,b−0,c−0 i.e. a,b,c

So, the equation of the plane passing through P(a,b,c), the direction ratios of the normal to which are a,b,c is

a(x−a)+b(y−b)+c(z−c)=0

⇒ax+by+cz=a

2

+b

2

+c

2

.

Answer 2

this is answer hope help ful for you