Question

passing through the points (-1 -2)and (5, 3)
Find the equation line​

Answer 1

Step-by-step explanation:

y2-y1/x2-x1 =. Gradient ( m)

= 3--2 /5--1

= -3/6

y = -3/6x + c

you can substitute x and y as either of ( - 1 ,-2) or ( 5,3) either is fine

-2 = -3/6 X -1 + c

-2 = -0.5 +c

c = -2 +0.5

• c = -1.5

y = 0.5x -1.5

Answer 2

Answer:

y=(5/6)x-7/6

Step-by-step explanation:

(x1,y1)=(-1,-2)

(x2,y2)=(5,3)

(y2-y1)/(x2-x1)=m

m=(3-(-2))/(5-(-1))

m=(3+2)/(5+1)

m=5/6

To find equation

y=mx+b

(-1 -2)=(x,y)

-2=5/6(-1)+b

-2=-5/6+b

-2+(5/6)=b

-12+5/6=b

b=-7/6

y=mx+b

y=(5/6)x-7/6

y=5x/6-7/6

y=1/6(5x-7)