Question

path of bomb released from an aeroplane moving with uniform velocity at certain height as observed by the pilot is.. ​

Answer 1

Answer:

I can't understand your questions please ask properly

Answer 2

ANSWER:

The pilot will observe the path of bomb in the shape of a parabola.

EXPLANATION:

   The velocity with which the plane is moving along is horizontal and constant. The velocity of the pilot and the plane are taken equivalent. The path of bomb falling will move directly below the plane, making the x-coordinate; x = ut and the y axis of the falling bomb is taken as$y=-\frac{1}{2} g t^{2}$ therefore, the path equation of the bomb is$y=-\frac{1}{2} g t^{2}= -\frac{1}{2} g\left(\frac{x}{u}\right)^{2}=\left(y=k x^{2}\right)$ now as we can seethe equation as $y=k x^{2}$

Therefore, by the equation path of the bomb drop we can say that the pilot will see the path of bomb drop as parabola.