Question

path of projectile (projected with angle θ with the vertical 0° θ 90°) as seen from ground is​

Answer 1

Explanation:

Let a body is projected with speed u m/s inclined 0 with horizontal line. Then, vertical component of u, uy = ucose

Horizontal component of u,u = = usine acceleration on horizontal, ax = 0 acceleration on vertical, ay = -g

Now, use formula,

X = = uxt

X = ucose.t

x/ucose-

-(1)

Again, y = uyt + 1/2ayt² y = usinet - 1/2gt²

Put equation (1) here,

y = usine x x/ucose - 1/2g x x²/u²cos²0 = tanex - 1/2gx²/u²cos²0

y = tano.x

gx²

2u² cos²0

This equation is similar to Standard equation of parabola y = ax² + bx + c her, a, b and c are constant

So, A projectile motion is parabolic motion

Answer 2

Answer:

the spiritual or immaterial part of a human being or animal, regarded as immortal.

Explanation:

thank you so much for your answers

and I don't have Iňßţä but we can be friends here, what do you say

am seeing you after a long time