Question

patient a a and patient b have to visit the doctor every 8 days and 10 days respectively after how many days will both the patients need the doctor on the same day ​

Answer 1

Answer:

we need to find the LCM of 8 and 10 days in this case

factors of 8=2x2x2

factors of 10=2×5

LCM is the product (multiplication) of all factors

hence, LCM(8,10)= 2x2x2x5=8x5=40

They will need the doctor on the same day after 40 days.

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Answer 2

patient A : 1,9,17,25,33,41

patient B : 1,11,21,31,41

both the patients need the doctor on the same day at day 41