patterns i++ and j-- c program
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Answer:
cout<<"\n enter any no.";
cin>>n;
if(n<=0)
{for(int i=0;i<=n;i++)
cout<<i;
}
else
{for(int j=0;j<=n;j--)
cout<<j;
}
Explanation:
angelgirl55:
plzz mark as brainliest
pls could u write a program based on that
plzz mark as brainliest
plzz mark as brainliest.............
i dont konw how to mark
im new to this app
below my answer there is written brainliest answer just click on that
sry nthng is showing below the answer
OK
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