Math, asked by sampadatekadpande, 4 hours ago

Paul can do a piece of work in 25 days. Mike and Paul can do the same work in 15 days. The number of days taken by Mike to do the same piece of work is:​

Answers

Answered by amitnrw
1

Given :  Paul can do a piece of work in 25 days.

Mike and Paul can do the same work in 15 days.

To Find : The number of days taken by Mike to do the same piece of work is:​

Solution:

 Paul can do a piece of work in 25 days.

=>  Paul can do  work in 1 day = 1/25

Mike can do a piece of work in  d days

=> Mike can do  work in 1 day = 1/d

Mike and Paul can do the same work in 15 days.

=> Mike and Paul can do  work in 1 day = 1/15

Hence :

1/25  + 1/d  = 1/15

=> 1/d  = 1/15  - 1/25

=> 1/d  = ( 5 - 3) /75

=> 1/d  = 2/75

=> d = 75/2

Mike to do the same piece of work  in  75/2 = 37.5 Days

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Answered by vaibhav13550
0

Answer:

Paul can do a piece of work in 25 days. => Paul can do work in 1 day = 1/25

Mike can do a piece of work in d days => Mike can do work in 1 day = 1/d

Mike and Paul can do the same work in 15

days. => Mike and Paul can do work in 1 day = 1/15

Hence :

1/25 1/d = 1/15

=> 1/d = 1/15 - 1/25 => 1/d =(5-3)/75

=> 1/d = 2/75

=> d= 75/2

Mike to do the same piece of work in 75/2 =

37.5 Days.

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