Question

Paul, Colin and Brian are waiters.
One night the restaurant earns tips totalling £71.10.
They share the tips in the ratio 2:3:4.
How much more does Colin get over Paul?
£?

Answer 1

let the common multiple be x.

according to given condition,

2x + 3x + 4x = 71.10

9x = 71.10

x = 71.10/9

x =7.9...

PAUL = 2X = 2 × 7.9= £15.8

COLIN =3X = 3 × 7.9 = £23.7

BRIAN = 4X = 4 × 7.9 = £31.6

oveegetting of Colin on Paul =

tip gained by Colin- tip gained by Paul

= 23.7 - 15.8

=£7.9

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Answer 2

$\underline{\sf{Given:-}}$

Three waiters named Paul, Colin and Brain. One night the restaurant earns tips totalling £71.10.

The given tip shared by them in the ratio 2:3:4.

$\underline{\sf{Assume:-}}$

Let the tip received by -

• Paul = 2M
• Colin = 3M
• Brain = 4M

$\underline{\sf{As\:per\:the\:given\:condition:-}}$

Total tip earned or received by three of them (waiters) is £71.10.

Means, the sum of ratio of their received tip is equal to total tip.

$\implies\:\sf{2M+3M+4M\:=\:71.10}$

$\implies\:\sf{9M\:=\:71.10}$

$\implies\:\sf{M\:=\:\frac{71.10}{9}}$

$\implies\:\sf{M\:=\:\frac{7110}{900}}$

$\implies\:\boxed{\sf{M\:=\:7.9}}$

Therefore,

Tip received by -

• Paul = 2M = 2(7.9) = £ 15.8
• Colin = 3M = 3(7.9) = £ 23.7
• Brain = 4M = 4(7.9) = £ 31.6

Also, we have to find that how much more does Colin get over Paul.

From above calculations we know that, tip received by Colin is £ 23.7 and Paul is £ 15.8.

To find how much does Colin get over Paul, just subtract their received moneys.

(bigger value - smaller value) or (Money received by Colin - Money received by Paul)

$\implies\:\sf{23.7-15.8}$

$\implies\:\sf{7.9}$

Therefore,

Colin get £ 7.9 more than Paul.

We can solve it by AP method too.

We have AP = 15.8, 23.7, 31.6

What we have to do is, find the common difference (d).

Here, a1 = 15.8, a2 = 23.7 and a3 = 31.6

So, d = a2 - a1 or a3 - a2

→ 23.7 - 15.8 or 31.6 - 23.7

→ 7.9

So, Colin get £ 7.9 more than Paul.