Paul drops a stone from a bridge that is 20m high above the water, ignore air resistance and calculate the velocity at which the stone will hit the water under the bridge
Heylo
Answers
Answered by
0
Answer:
v=20m/s
Solution:
Correct option is B)
Distance (s) =20 m
Initial velocity =0 m/s
g=10 m/s ^2
By using the formula:
v ^2 =u^ 2+2as
v ^2 =0^2+2×10×20
v^2=400
v^2= root 400
v=20m/s
mark me as brainliest
Similar questions