Question

Paul is 20 years old. He is four times older than his sister
How old will Paul be when he is twice as old as his sister?​

Answer 1

Given:

Paul is 20 years old and he is four times older than his sister

To find:

The age of paul when he is twice as old as his sister

Calculation :

Let the age of her sister be x, then from the given data

=> 4x = 20

=> x = 5 years

The age of her sister is 5 years

In the second case, paul is twice as old as his sister

=> Age of paul = 2(x)

=> Age of paul = 10 years

Paul will be 10 years old when he is twice as old as his sister

Answer 2

Answer:

30

Step-by-step explanation:

Paul age = 20

Sister age = x

Paul age is 4times of sister's age i.e 5

when 2x = x

mean Paul age is 10 + 20 = 30