Question

Paul is twice as efficient worker as lisa and together they can do a work in 30 days ​

Answer 1

Answer:

Let the Paul =2x

lisa=x

=30

2x+x=30

3x=30

x=30/3

10

Explanation:

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Answer 2

Solution:

From the given, ratio of the efficiency of Paul and Lisa, P: L is 2:1

Total number of days in which both can complete the work is 30 days.

Here, the total efficiency is 2+1=3

$\text { work done }=\text { efficiency } \times \text { time }$

$3 \times 30=90$

So, the total work done is 90.

Work done by Paul in 30 days is

$2 \times 30=60$

Work done by Lisa in 30 days is

$1 \times 30=30$

If Paul alone does the work then,  

$90=2 \times \text { time taken }$

Time taken by Paul alone to do the work is 45 days.

If Lisa alone does the work,

$90=1 \times \text { time taken }$

Time taken by Lisa alone to do the work is 90 days.