Question

Paul is x years old and his father's age is twice the square of Paul's age . Ten years hence , father's age will be 4 times Paul's age. find their present ages .

Answer 1

40 is the age of his father

Answer 2

Let Paul age=x

Father= 2x

10 years ago

Paul=x-10

Father=2x-10

4(x-10)=2x-10

4x-40=2x-10

4x-2x=-10+40

2x=30

X=30/2

x=15

2x=30