Question

Paul is x years old and his father's age is twice the square of Paul's age . Ten years hence , father's age will be 4 times Paul's age. find their present ages .


Chap : Quadratic Equations , Class 10 .

Plz help !!

Answer 1

Let Paul age=x
Father= 2x
10 years ago
Paul=x-10
Father=2x-10
4(x-10)=2x-10
4x-40=2x-10
4x-2x=-10+40
2x=30
X=30/2
x=15
2x=30

Answer 2

Hello friend!
Here's ur answer!
Let Paul's age be x
So, Fathers age= 2x
10 years ago,
Pauls age=x-10
Fathers age =2x-10
4(x-10)=2x-10
4x-40=2x-10
4x-2x=-10+40
2x=30
x=30/2
x=15
2x=30
Hope it helps!!☺
Thanks!!☺